5t^2-31t+6=0

Solution for 5t^2-31t+6=0 equation:

5t^2-31t+6=0

a = 5; b = -31; c = +6;
Δ = b2-4ac
Δ = -312-4·5·6
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*5}=\frac{2}{10}
=1/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*5}=\frac{60}{10}
=6
$